Question

from a circular cardboard of diameter 28m 2 circle of radius 3.5m 2 right triangle whose sides containing right angles measure ingc8m and 6m and a square of side 5m are remov5 find the area of remains cardboard ​

Answer 1

Answer:

radius = 3.5

area of the 2 circles=$2\pi r^{2}$

                               = 2 x $\frac{22}{7}$ x $r^{2}$

                               =2 x $\frac{22}{7}$ x 3.5 x 3.5

                               =77$m^{2}$

area of triangle=($\frac{1}{2} bh$)x 2

                         =( $\frac{1}{2}$ x 8 x 6) x 2

                         = 48$m^{2}$

area of square=s x s

                        = 5 x 5

                        = 25$m^{2}$

total area of all shapes=77+48+25

                                     = 150$m^{2}$

area of the big circle=$\pi r^{2}$

                                 =$\frac{22}{7}$ x 14 x 14

                                 =$616m^{2}$

area of remaining circle=616-150

                                      =466$m^{2}$