From a circular cylinder of diameter 10 cm and height 12 cm, a conical cavity of the
same base radius and of the same height is hollowed out. Find the volume and the
whole surface of the remaining solid. (Take t = 3.14)
13]
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Solution :-
The diameter of a circular cylinder = 10cm
Therefore,
Radius of the circular cylinder = 10/2 = 5cm
The Height of the circular cylinder = 12cm
Therefore,
The volume of the circular cylinder = πr^2h
Subsitute the required values,
Volume of circular cylinder
= 3.14 * 5 * 5 * 12
= 3.14 * 25 * 12
= 3.14 * 300
= 942cm^2
Now
A conical cavity of same base ,radius and of the same Height
Therefore,
As we know that,
Volume of cone = 1/3πr^2h
Volume of cone
= 1/3 * 3.14 * 5 * 5 * 12
= 3.14 * 25 * 4
= 3.14 * 100
= 314cm^2
So,
The volume of the remaining solid
= Volume of cylinder - Volume of cone
= 942 - 314
= 628cm^2
Hence, The volume of the remaining solid is 628cm^2 
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