From a circular cylinder of diameter 10cm and height 12cm,a conical cavity of the same base radius and of the same height is hollowed out.Find the volume and the whole surpace of the remaining solid. Leave the answer in pie.
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Answered by
39
Volume of cylinder = pie .25.25.12
volume of cone = 1/3. pie. 25.25. 12
vol. of remaining solid = 2/3. 25. 25.12 pie= 8×625 pie= 5000pie
surface area,of cylinder = 2pie ×5 ( 12+5) = 170 pie
surface area of cone = pie. 5.( √144+25 +5) = pie.5. 18 = 90 pie
area of base = pie .25 = 25pie
so. surface area of remaining solid = TSA of cylinder + TSA of cone - 2pie. r.r
= 170 pie + 90 pie - 2×25 pie
= 170 pie + 90 pie -50 pie
= 210 pie
volume of cone = 1/3. pie. 25.25. 12
vol. of remaining solid = 2/3. 25. 25.12 pie= 8×625 pie= 5000pie
surface area,of cylinder = 2pie ×5 ( 12+5) = 170 pie
surface area of cone = pie. 5.( √144+25 +5) = pie.5. 18 = 90 pie
area of base = pie .25 = 25pie
so. surface area of remaining solid = TSA of cylinder + TSA of cone - 2pie. r.r
= 170 pie + 90 pie - 2×25 pie
= 170 pie + 90 pie -50 pie
= 210 pie
Answered by
44
Check the attachment. Hope it helps
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adityaTheErrorist:
this is the correct answer :)
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