From a circular sheet of radius 14 cm, 2 circles of radius 2.1 cm and a rectangle of length 1.6 cm and breadth 0.5 cm is removed. Find the area of the remaining sheet.
Answers
Answer:
the area of remaining sheet=536cm2
Step-by-step explanation:
Given :- From a circular sheet of radius 14 cm, 2 circles of radius 2.1 cm and a rectangle of length 1.6 cm and breadth 0.5 cm is removed. Find the area of the remaining sheet ?
Solution :-
we know that,
- Area of circle = π * (radius)² .
- Area of rectangle = Length * Breadth .
so,
→ Area of remaining sheet = Area of seat - (Area of 2 circles + Area od rectangle.)
Putting all values now, we get,
→ Area of remaining sheet = π(14)² - [2*{π*(2.1)²} + 1.6 * 0.5]
→ Area of remaining sheet = 22*14*2 - [2*22*2.1*0.3 + 0.8]
→ Area of remaining sheet = 616 - (27.72 + 0.8)
→ Area of remaining sheet = 616 - 28.52
→ Area of remaining sheet = 587.48 cm². (Ans.)
Hence, Area of remaining sheet is 587.48 cm².
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