From a circular sheet of radius 4 cm ,a circle of radius 3 cm is removed. find the area of the remaining sheet. ( take π = 3.14)
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Answered by
804
Area of the circle with radius 4 cm = πr² = π(4)² = 16 π cm²
Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm²
Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm²
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Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm²
Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm²
Hope This Helps You!
Answered by
511
Area of circular shet=4cm
area of sheet=πr²
=π×(4)²=16π
area of circle removed=πr²
=π×(3)² =9π
area of remaining sheet=16π-9π
=7π=7×3.14
=21.98cm².
area of sheet=πr²
=π×(4)²=16π
area of circle removed=πr²
=π×(3)² =9π
area of remaining sheet=16π-9π
=7π=7×3.14
=21.98cm².
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