From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet.
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The area of the circular sheet with 4cm radius is, A=πr2.
The area of the circular sheet with 3cm radius is, A=πr2.
Since the circle with radius 3cm is removed, then the remaining area is, A=16π−9π
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Radius of circular sheet (R) = 4 cm
A circle of radius to be removed (r) = 3 cm
The area of remaining sheet = πR² - πr²
= π (R² - r²)
= 3.14 (4² - 3²)
= 3.14 (16 - 9)
= 3.14 × 7
= 21.98 cm²
The area of the remaining sheet is 21.98 cm²
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