Question

from a circular sheet of radius 4cm ,a circle of radius 3cm is removed . find the area of the remaining sheet (take r= 3.14)
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Answer 1

given:Area of circular sheet=4cm

Solutions:

firstly,

• area of sheet=πr²=π×(4)²=16π

• area of circle removed=πr²

=π×(3)² =9π

Now,

area of remaining sheet=16π-9π

=7π=7×3.14

=21.98cm².

Answer 2

$\huge\bf{\purple{Solution:-}}$

$\sf\bullet Radius\:of\: sheet=4cm\\ \\ \sf\bullet Radius\:of\: circle \: removed= 3cm$

Now

$\bf\underline{\red{According\:To\: Question:-}}$

First find the Area of sheet

$\boxed{\sf{\dag{\:\:Area\:of\: circle=\pi r{}^{2}}}}$

$\sf\implies Area\:of\:sheet =3.14\times (4){}^{2}\\ \\ \sf\implies Area=3.14\times 16\\ \\ \sf\implies Area=50.24cm{}^{2}$

Now the Area if circle removed

$\sf\implies Area\:of\: circle=3.14\times (3){}^{2}\\ \\ \sf\implies Area= 3.14\times 9\\ \\ \sf\implies Area= 28.26cm{}^{2}$

So find the Area if remaining sheet

$\underline{\dag{\sf{\:\:Area\:of\: remaining\:sheet= Area\:of\:sheet-Area\:of\: circle}}}$

$\sf\implies Remaining\:sheet= 50.24-28.26\\ \\ \sf\implies Area_{remaining}= 21.98cm{}^{2}$

$\boxed{\sf{\red{Area\:of\: remaining\:sheet=21.98cm{}^{2}}}}$