Question

From a circular sheet of radius 6cm , a circle of radius 4cm is removed, find the area of the remaining sheet​

Answer 1

Answer:                                                                                                                          20π cm² or 62.83 cm²

Step-by-step explanation:

Area of first circle =  πr²  

                             =  π×6² =36π cm²

Area of second circle =  πr²

                                   = π×4² =16π cm²

Area of remaining circle = 36π - 16π =20π cm²= 62.83 cm²

Answer 2

$Area \: of \: big \: circle \: = \pi \gamma ^{2} \\ \\ a \: = \frac{22}{7} \: \times 6 \: \times \: 6 \\ a = 113.14 \: {cm}^{2} \\ . \: Area \: of \: the \: small \: circle \: = \pi \gamma {2} \\ a \: = \: \frac{22}{7} \times 4 \times 4 \\ a \: = 50.28 {cm}^{2} \\ . \: Area \: of \: the \: remaining \: part \: = \\ Area \: of \: big \: crcle \: - .Area \: of \: \\ small \: circle \\ . \: Area \: of \: remaining \: part \: = \\ ( \: 113.14 \: - 50.28 \: ) \: cm {2} \\ . \: Area \: of \: remaining \: part \: \\ = 62.86 {cm}^{2}$

I HOPE THIS WILL HELP YOU.