From a circular sheet of radius 7 cm, two circles of radii 1.4 cm
each, a triangle of base 3 cm and height 2 cm and a rectangle of
length 4 cm and breadth 2 cm are removed (Fig. 15.28]. Find the
remaining area.
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Area of circular sheet = 22/7*7*7
=154
Area of two circles=22/7*2.8*2.8 (sum of two circles radii) =24.64
Area of triangle =1/2*3*2
=3cm
Area of rectangle =4*2
=8
sum of all removed part=24.64+3+8
=35.64
subtract the area of circular sheet from areas of removing parts
=154-35.64=118.46ans.
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