From a cliff of 49 m high, a man drops a stone. One second later, he throws another stone. They both hit the ground at the same time. Find out the speed with
which he threw the second stone
Nn.
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Explanation:
i
EXPLANATION.
From a cliff 49 m high a man drops a stone.
one Second later, he throws another stone.
They both hit the ground at the same time.
Find out the speed with which he threw
the second stone.
Answered by
0
Answer:
for first stone
h = 49m
g = 9.8m/s²
t = ?
u = 0
apply
h = ut + gt²/2
49 = 0 + 9.8t²/2
t² = 10
t = √10 = 3.16s
for second stone
t = 3.16 - 1 = 2.16s
h = 49m
g = 9.8m/s²
u = ?
again apply
h = ut + gt²/2
49 = u*2.16 + 9.8*2.16²/2
49 = 2.16*u + 22.86
26.14/2.16 = u
u = 12.10m/s
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