From a cone of radius 40 cm a cone of radius 16 cm and height 12 cm is cut from the top so that the circular bases of these cones are parallel . Find the volume of frustum so obtained.
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volume of frustum = 1/3 πh (r1^2 + r2^2 + r1×r2)
= 1/3 ×3.14 × 12 (40^2 +16^2
+ 40×16
= 3.14×4 ( 1600+256+ 6400)
= 12.56 × 8256
= 103695.36 cubic cm
= 1/3 ×3.14 × 12 (40^2 +16^2
+ 40×16
= 3.14×4 ( 1600+256+ 6400)
= 12.56 × 8256
= 103695.36 cubic cm
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