From a dam,water is pouring down at the rate of 150 kg/s, on the blades of a turbine.if a ball dropped from the same dam takes 2✓5 s to hit the turbine,then the power delivered to the turbine is approximately equal to
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Hi friend,
We have to find the height.
So , S=ut +1/2 at²
U=0
S= 1/2 ×10×(2√5)²
S=100m.
Power = work done /time
Power = mgh /time.
( here the ball comes to rest.so work done acts as potential energy).
Power= 150×10×100/2√5
power =33542 watts or 33.542 kW.
Hope this helped you a little!!!
We have to find the height.
So , S=ut +1/2 at²
U=0
S= 1/2 ×10×(2√5)²
S=100m.
Power = work done /time
Power = mgh /time.
( here the ball comes to rest.so work done acts as potential energy).
Power= 150×10×100/2√5
power =33542 watts or 33.542 kW.
Hope this helped you a little!!!
need some clarification answer is not there in options
Answer is 150 kW
I had rectified it
I had written in another questions
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power =33542 watts or 33.542 kW.