From a dam, water is pouring down at the rate of
150 kg/s, on the blades of a turbine. If a ball
dropped from the same dam takes 2 5 s to hit the
turbine, then the power delivered to the turbine is
approximately equal to (Take g = 10 m/s2)
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Height of the dam=
S= ut + 1/2 g t²
Here initial velocity (u) = 0.
S= 0.5 × 10×(2√5)²
S= 100m.
power= potential energy / time
= mgh/time
= 150×10×200/2√5
= 15000 watt = 15kw.
S= ut + 1/2 g t²
Here initial velocity (u) = 0.
S= 0.5 × 10×(2√5)²
S= 100m.
power= potential energy / time
= mgh/time
= 150×10×200/2√5
= 15000 watt = 15kw.
rahulgohil1001:
sorry but its wrong
(2) 150 kW
(3) 125 kW
(4) 15.5 kW
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