From a dam, water is pouring down at the rate of 150kg/s, on the blades of a turbine. If a ball dropped from the same dam takes 2 under root 5 second to hit the turbine is aaproximately equal to (Take g = 10 m/s square) (1) 15w (2) 150kw (3) 125kw (4) 15.5kw
Answers
Answered by
19
height of the dam s = 1/2 g t^2
s = 1/2 × 10×(2 sqrt(5))^2 = 100m.
Power in the water striking the turbines = m g h / time
P = 150 kg/s* 10 m/s^2* 100 m
= 150 kW
s = 1/2 × 10×(2 sqrt(5))^2 = 100m.
Power in the water striking the turbines = m g h / time
P = 150 kg/s* 10 m/s^2* 100 m
= 150 kW
BrainlyGood:
:) . Hope it's correct
Answered by
9
Hi friend,
Height of the dam=
S= ut + 1/2 g t²
Here initial velocity (u) = 0.
S= 0.5 × 10×(2√5)²
S= 100m.
power= potential energy / time
= mgh/time
= 150×10×200/2√5
= 15000 watt = 15kw. Hope this helped you a little!!!
Height of the dam=
S= ut + 1/2 g t²
Here initial velocity (u) = 0.
S= 0.5 × 10×(2√5)²
S= 100m.
power= potential energy / time
= mgh/time
= 150×10×200/2√5
= 15000 watt = 15kw. Hope this helped you a little!!!
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