Question

From a deck of 52 playing crads,kings,Ace and 10 of clubs were removed and remaining cards were well shuffled.if a card is drawn at random from the remaining ,Find the probability of getting a card of (a)club (b) ace (c)diamond king (d)club5​

Answer 1

Answer:

hey mate according to question

total number of cards is 52

and 10 card were removed

so the remaining cards are 52 - 10 = 42

(a) probability of club

10 club were removed given in question

so the remaining is 13 - 10 = 3

so the answer is 3/42

1/14

(b) probability of ace

4/42 so the answer is 2/21

(c) probability of diamond king

2/42 so the answer is 1/21

(d) probably of club 5

but in question 10 card are removed or only 13 are there so how it's possible

but the answer is

-2/42 that is -1/21

Answer 2

Step-by-step explanation:

above answer is the correct answer...