Question

From a group of 2 boys and 3 girls two children are selected at random. Then the probability such that at least one boy is selected

Answer 1

boys = 2
girls = 3

2 are to be selected from the 5.

total ways = 5C2 = 10

ways in which no boys selected = ways in which we can select 2 girls = 3C2 = 3

So ways in which atleast one boy is selected = 10-3 = 7

Probability = 7/10