from a mettalic plate which is a squareof side 10 cn a circular disc of diameter 3.5 cn is cutt off find tge weighr of the remaining part if 1sq cn of the plate weight 0.5 gm
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REF.Image.
Area of square plate = d
2
So mass M
s
=pd
2
p = mass per unit area.
Area of circular dies = π(
2
d
)
2
=
4
πd
2
⇒ mass M
c
=P
4
nd
2
trations c as the origin the coordinate
of center of mass of the square plate
will be x
5
=0 & that for circular
disc will be x
c
=
2
3d
So coordinate of center of mass of system
will be X=
m
s
+M
c
m
s
x
s
+m
c
x
c
=
pd
2
+
4
πd
2
p
0+
4
pπd
2
2
3d
⇒X=
2(π+4)
3πd
from center of square plate
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