From a pack of 52 playing cards, jacks and kings of red colour and queens and aces of black colour are removed. The remaining cards are mixed and a card is drawn at random. Find the probability that the drawn card is (i) a black queen (ii) a card of red colour (iii) a jack of black colour (iv) a face card
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9
First one is 0
Second one is 22 /44
Third one is 4/44
Fourth one is 6/44
Please mark my answer as the brainliest
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Answer:
Total number of outcomes = 52
Cards removed = 2+2+2+2 = 8[2 jack, 2 queen, 2 king and 2 aces of red colour]
Remaining number of cards = 52 – 8=44
Total number of outcomes = 44
(i) Favourable outcomes = 2 [There are 2 black queen]
Required probability =
(ii) Favourable outcomes = number of red cards left = 26 – 8=18
Probability for a red card =
(iii) Favourable outcomes = Number of black jacks = 2
Required probability =
(iv) Number of picture cards left =2+2+2 = 6 [jack, queen, King are picture cards]
Required probability =
(v) Honorable cards [ace, jack, queen and king]
No. of honorable cards left = 2+2+2+2=8
Required probability =
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