Question

From a pack of 52 playing cards jacks, queens, kings and aces of red colour are removed. From the remaining, a card is drawn at random. Find the probability that the card drawn is
(i) a black queen   (ii) a red card   (iii) a black jack   (iv) a picture card (Jacks, queens and kings are picture cards) 

​

Answer 1

Answer:

ss=52-8=44

1/24

13/24

1/24

1/8

Step-by-step explanation:

MARK me BRAINLIEST pleasee

Answer 2

· · • •✤ Aɳടɯҽɾ ✤ • • · ·

⤵️⤵️

Total no. of cards in a pack =52

After removing red-colored - jack, queen, king, and aces,

No. of cards =52−8=44 and

No. of red cards =26−8=18.

Solution1

Let E be the event of getting a black queen from pack

We know that, Probability P(E) = (Total no.of possible outcomes)/(No.of favorable outcomes)

= 44 C¹/²C¹

= 44/2

= 22/1

Solution(ii):

( Selecting 1 out of 44 items) a red card is picked.

Let E be the event of getting a red card from the pack

We know that, Probability P(E) = (Total no.of possible outcomes)/(No.of favorable outcomes)

= 44C 1/18 C 1

= 44/18

= 22/9

Solution(iii):

We know that, Probability P(E) = (Total no.of possible outcomes)/(No.of favorable outcomes)

= 44c¹/ ²C¹

= 44/2

= 22/1

Solution(iv):

We know that, Probability P(E) = (Total no.of possible outcomes)/(No.of favorable outcomes)

= 44C¹/6 C ¹

= 44/6

= 22/3

· · • • • ✤ • • • · ·