Question

6. An ore contains 15% of iron. How much ore will be required to get 36 kg of iron ?
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Content of iron in ore =15%

= 15kg

∴15kg iron in 100 kg ore

$∴ In \: 36kg \: iron = \frac{100}{15} \times 36$

= 240 kg of ore .

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