from a pack of 52 playing cards, Jacks, Queens, kings and aces of red colour are removed. from the remaining a card is drawn at random. find the probability that the card drawn is 1.a black Queen 2.a red card 3.a Black jack 4. a honorable card
card
Answers
Cards left = 44
1.)= black queens are 2 so
22/44=1/22
2.)red card =20
so 20/44 =5/11
3.) black jack =2
so 2/44=1/22
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Answer:
Total number of outcomes = 52
Cards removed = 2+2+2+2 = 8[2 jack, 2 queen, 2 king and 2 aces of red colour]
Remaining number of cards = 52 – 8=44
Total number of outcomes = 44
(i) Favourable outcomes = 2 [There are 2 black queen]
Required probability =
(ii) Favourable outcomes = number of red cards left = 26 – 8=18
Probability for a red card =
(iii) Favourable outcomes = Number of black jacks = 2
Required probability =
(iv) Number of picture cards left =2+2+2 = 6 [jack, queen, King are picture cards]
Required probability =
(v) Honorable cards [ace, jack, queen and king]
No. of honorable cards left = 2+2+2+2=8
Required probability =