Math, asked by timeforstudy, 1 year ago

from a pack of 52 playing cards, Jacks, Queens, kings and aces of red colour are removed. from the remaining a card is drawn at random. find the probability that the card drawn is 1.a black Queen 2.a red card 3.a Black jack 4. a honorable card

card​

Answers

Answered by tanmayhada
1

Cards left = 44

1.)= black queens are 2 so

22/44=1/22

2.)red card =20

so 20/44 =5/11

3.) black jack =2

so 2/44=1/22

hope u like it ,plz mark as brainliest


timeforstudy: Fourth point ka ans nhi deya
Answered by Anonymous
0

Answer:

Total number of outcomes = 52

Cards removed = 2+2+2+2 = 8[2 jack, 2 queen, 2 king and 2 aces of red colour]

Remaining number of cards = 52 – 8=44

Total number of outcomes = 44

(i) Favourable outcomes = 2 [There are 2 black queen]

Required probability =

(ii) Favourable outcomes = number of red cards left = 26 – 8=18

Probability for a red card =

(iii) Favourable outcomes = Number of black jacks = 2

Required probability =

(iv) Number of picture cards left =2+2+2 = 6 [jack, queen, King are picture cards]

Required probability =

(v) Honorable cards [ace, jack, queen and king]

No. of honorable cards left = 2+2+2+2=8

Required probability =

Similar questions