From a piece of land 1/3 brought by A and 1/3 remaining brought by b if 600m is left find the total land
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Brought by A = 1/3
remaining = 1-1/3 = 2/3
Brought by B = 1/3 * 2/3 = 2/9
remaining = 1- 1/3 - 2/9 = 4/9
4/9 = 600
1 = 600*9/4 = 1350m
remaining = 1-1/3 = 2/3
Brought by B = 1/3 * 2/3 = 2/9
remaining = 1- 1/3 - 2/9 = 4/9
4/9 = 600
1 = 600*9/4 = 1350m
TARUN2693:
Give my answer brainley
Answered by
1
Hey sup!
Let the total land be x.
As per the question,
A bought = 1/3 of x= 1/3*x=x/3.
Remaining=x-x/3=2x/3.
B bought=1/3 of 2x/3=1/3*2x/3=2x/9.
Remaining=2x/3-2x/9=4x/9.
Also remaining=600m
4x/9=600.
=>4x=600×9.
=>x=(600×9)/4.
=>x=150×9.
=>x=1350m.
So, the total land is 1350m or 1.35km
Hope it helps.
Let the total land be x.
As per the question,
A bought = 1/3 of x= 1/3*x=x/3.
Remaining=x-x/3=2x/3.
B bought=1/3 of 2x/3=1/3*2x/3=2x/9.
Remaining=2x/3-2x/9=4x/9.
Also remaining=600m
4x/9=600.
=>4x=600×9.
=>x=(600×9)/4.
=>x=150×9.
=>x=1350m.
So, the total land is 1350m or 1.35km
Hope it helps.
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