Question

From a place on the ground that is 20m away from a wall, a bullet is fired aiming at 50m high mark on the wall. The location of the bullet is shown by a circular dot at some point of time. Where on the wall will the bullet hit?

Answer 1

This is can be solved with help of horizontal projectile concept.

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below ,

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula ,

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula , S = ut + 1/2at²

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula , S = ut + 1/2at² h = 0 - 1/2 × g × (0.1)² = 1/2 × -10 × 0.01 m = -5cm , here negative sign indicates bullet does hit below the reference level.

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula , S = ut + 1/2at² h = 0 - 1/2 × g × (0.1)² = 1/2 × -10 × 0.01 m = -5cm , here negative sign indicates bullet does hit below the reference level.Hence answer is 5cm

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula , S = ut + 1/2at² h = 0 - 1/2 × g × (0.1)² = 1/2 × -10 × 0.01 m = -5cm , here negative sign indicates bullet does hit below the reference level.Hence answer is 5cm

This is can be solved with help of horizontal projectile concept.In horizontal, acceleration act on bullet is zero.so, distance = speed of bullet × time taken 150 = 1500 × t t = 0.1 sec , hence bullet strikes the ground in 0.1 sec Now , how much below does the bullet hits the target.Let bullet hits the target h m below , in vertical, initial velocity = 0 and acceleration = -g so, use formula , S = ut + 1/2at² h = 0 - 1/2 × g × (0.1)² = 1/2 × -10 × 0.01 m = -5cm , here negative sign indicates bullet does hit below the reference level.Hence answer is 5cm Plz mark me as brainliest