From a point across a river, the angles of depression of the banks on opposite sides of the river are 30° and 45° respectively. If the bridge is at a height of 5m from the banks, find the width of river.
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In figure, A and B are points on th bank on opposite sides of river.
⇒ AB is the width of the river.
P is the point on bridge at a height =30m i.e. DP=30m
Now, AB=AD+DB
In right angled △ADP,
∠A=30
o
⇒ tan30
o
=
AD
PD
⇒
3
1
=
AD
30
∴ AD=30
3
m
In right angled △PDB,
tan45
o
=
DB
PD
⇒ 1=
DB
30
∴ DB=30m
Now, AB=BD+AD=30+30
3
m=30+30(1.732)=81.96m
∴ The width of river is 81.96m
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refer the 3 attachment above
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