From a point on a bridge across a river the angle of depression of the banks on opposite sides of the river are 60° and 45° respectively. If the bridge is at a height of 9 meter form the banks, Find the width of river.
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Let the river banks be C and D respectively
Given: Height of the bridge, AB = 9m
To find: Width of the river i.e CD
Angle of depression to bank C from A
tan60° =
=> √3 =
=> BC = 9√3 m
Angle of depression to bank D from A
tan45° =
=> 1 =
=> AB = BD
So, BD = 9 m
Therefore, width of the river, CD = BC + BD
CD = 9√3 m + 9 m
CD = 9(√3 + 1) m
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