Question

From a point on a ground, 30m away from the foot of a tower, the angle of elevation of the top of the tower is 30, the height of the power is
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Answer 1

Answer

let the Height of the tower be H

So Tan 30 = Perpendicular/Height

=> Tan 30 = H /30

= 30×1/✓3h

= 30✓3/3

Height is 10✓3m

Answer 2

Answer:

In ∆ ABC,

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.