From a point on the circle x^2 + y^2 = a^2, tangents are drawn to the hyperbola x^2 - y^2 = a^2. Prove that the locus of the middle point of the chord of contact is (x^2 - y^2) ^2 = a^2( x^2 + y^2)
Answers
Answered by
29
Let a point P(x1, y1) be on the circle C1: x²+ y² = a². --- (1)
Let the tangents to the Hyperbola H1: x² - y² = a² ---- (2), from P be PQ and PR, touching H1 at Q(x2, y2) and R(x3, y3).
So PQ: x *x2 - y * y2 = a², and PR : x * x3 - y * y3 = a² --- (3)
As PQ and PQ pass through P,
x1 * x2 - y1* y2 = a² and x1 * x3 - y1 * y3 = a² --- (4)
Equation of QR - Chord of Contact containing Q & R - is clearly,
x1 * x - y1 * y = a². --- (5)
Midpoint of chord of contact QR is: S(α, β) = [ (x2+x3)/2, (y2 +y3)/2 ].
Adding two equations in (4), we get x1 α - y1 β = a² --- (6)
Equation of chord of contact QR of H1 with its mid point at S(α, β) is given by formula:
T = S1 --- (7)
ie., x α - β y - a² = α² - β² - a²
=> x α - y β = α² - β². --- (8)
Equations (5) and (8) represent the same Chord of contact QR:
So x1 / α = y1 / β = a²/(α² - β²)
or x1 = α a²/(α²+β²) and y1 = β a²/(α² - β²) --- (9)
Substitute (9) in eq (1) to get :
(a⁴ α² + a⁴ β² )/(α² - β²)² = a²
Replace S(α, β) by (x,y) to get the locus.
=> (x² + y²) a² = (x² - y²)²
Let the tangents to the Hyperbola H1: x² - y² = a² ---- (2), from P be PQ and PR, touching H1 at Q(x2, y2) and R(x3, y3).
So PQ: x *x2 - y * y2 = a², and PR : x * x3 - y * y3 = a² --- (3)
As PQ and PQ pass through P,
x1 * x2 - y1* y2 = a² and x1 * x3 - y1 * y3 = a² --- (4)
Equation of QR - Chord of Contact containing Q & R - is clearly,
x1 * x - y1 * y = a². --- (5)
Midpoint of chord of contact QR is: S(α, β) = [ (x2+x3)/2, (y2 +y3)/2 ].
Adding two equations in (4), we get x1 α - y1 β = a² --- (6)
Equation of chord of contact QR of H1 with its mid point at S(α, β) is given by formula:
T = S1 --- (7)
ie., x α - β y - a² = α² - β² - a²
=> x α - y β = α² - β². --- (8)
Equations (5) and (8) represent the same Chord of contact QR:
So x1 / α = y1 / β = a²/(α² - β²)
or x1 = α a²/(α²+β²) and y1 = β a²/(α² - β²) --- (9)
Substitute (9) in eq (1) to get :
(a⁴ α² + a⁴ β² )/(α² - β²)² = a²
Replace S(α, β) by (x,y) to get the locus.
=> (x² + y²) a² = (x² - y²)²
kvnmurty:
:-)
Similar questions