Question

from a point on the ground 40 metre away from the foot of a tower the angle of elevation of the top of the tower is 30 degree the angle of elevation of the top of the water tank is 45 degree find the height of the tower

Answer 1

Hello,

let h  m be the height of tower and  m be the depth of tank (as figure).

Now, in ΔABC:

tan30°=BC/AB;

1/√3=h/40;

h=40/√3 m     (1)

 In ΔABD:

tan45°=DC+BC/AB;

1=x+h/40;

x+h=40;

using (1):

x+40/√3=40;

x=40(1-1/√3) m

Then height of the tower = 40/√3 m,

and depth up tank :

40(1-1/√3)m

bye :-)

Answer 2

HEY MATE YOUR ANSWER IS HERE

REFFERED TO THE ATTACHMENT

THANKS FOR UR QUESTION HOPE IT HELPS