From a point on the ground at a distance 'a' from the foot of a pole, a ball is thrown at an angle of 45° such that it just touches the top of the pole and strikes the ground at a distance of 'b' on the other side of it. The height of the pole is P(a,h) h a = 45°
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Answer:
ab
a+b
Explanation:
let h be the height of the pole
we have y=x tan ( 1 - x )
r
since the top of pole lines on curve 1
height ( h ) = atan 45° ( 1 - a ) = a{a+ b-a}= ab
a+ b a+ b a + b
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