Question

rationalise the denominator 4√3-2√7/4√3+2√7?​

Answer 1

Answer:

$\frac{4 \sqrt{3} - 2 \sqrt{7} }{4 \sqrt{3} + 2 \sqrt{7} } \\ \frac{2(2 \sqrt{3} - \sqrt{7)} }{2(2 \sqrt{3} + \sqrt{7} } = \frac{2 \sqrt{3} - \sqrt{7} }{2 \sqrt{3} + \sqrt{7} } \\ \frac{2 \sqrt{3} - \sqrt{7} }{2 \sqrt{3} + \sqrt{7} } \times \frac{2 \sqrt{3} - \sqrt{7} }{2 \sqrt{3} - \sqrt{7 } } \\ \frac{(2 \sqrt{3} - \sqrt{7})(2 \sqrt{3} - \sqrt{7} }{12 - 7} \\ \frac{12 - 2 \sqrt{21} - 2 \sqrt{21} + 7 }{5} = \frac{19 - 4 \sqrt{21} }{5}$

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