From a point on the ground of the angle of elevation of the bottom and top of a communication tower fuxed on the top of 20 m high building are 45° and 60° find the height of the tower.
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TAN 45 °A=20/pb
1 = 20/pb
Pb=20m
Tan 60 °A=cA+20/pb
Route 3 =ca+20/20
20route 3= ca+20
20 root 3 - 20 =ca
20 ( route 3 - 1) = ca
Therefore the height of the tower is 20( route 3- 1)
1 = 20/pb
Pb=20m
Tan 60 °A=cA+20/pb
Route 3 =ca+20/20
20route 3= ca+20
20 root 3 - 20 =ca
20 ( route 3 - 1) = ca
Therefore the height of the tower is 20( route 3- 1)
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