from a point on the ground, the angle of elevation of the bottom and the top of a transmission tower fixed at the top of a 20m high building are 45°and60° respectively. find the height of the tower
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Answer:
in case of angle of botton=45degree
tan45=height/base
1=20/base
base=20m
now in case of angle of elevation of top=60degree
tan60=height/base
√3=h+20/20
20√3=h+20
h=20√3-20
h=20(√3-1)
h=20x0.732
h=14.64m
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