from a point on the ground the angle of elevation to the top and bottom of a 40 m transmission tower fixed at the top of a building are 45°and 60°respectively.find the height of the building
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Answer:
h=20(√3-1)
Step-by-step explanation:
Let DC be the tower and BC be the building. Then,
∠CAB=45° ,∠DAB=60° ,BC=20 m
Let height of the tower, DC=h m
In right △ABC,
tan45° = BC/ AB
1= 20 /AB
AB=20 m
In right △ABD,
tan60°=BD/AB
√3=h+20/20
h=20(√3-1)
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