From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower
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1
Take tan45(1) - you will get the base as 20 m
Then take tan60 - and you will get the height as 20* root 3
Then take tan60 - and you will get the height as 20* root 3
Answered by
3
let AB=tower BC =building dc = distance from point
take tan45= 1=20/dc so,. dc= 20m
tan 60= √3=. 20+AB/20
20√3-20=AB
AB=20(√3-1)
take tan45= 1=20/dc so,. dc= 20m
tan 60= √3=. 20+AB/20
20√3-20=AB
AB=20(√3-1)
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