From a point on the ground, the angles of elevation of the bottom and top of a
transmission tower fixed at the top of a 20 m high building are 450 and 600
respectively. Find the height of the tower.
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Answer:
Let DC be the tower and BC be the building. Then,
∠CAB=45°,∠DAB=60° ,BC=20 m
Let height of the tower, DC=h m.
In right △ABC,
tan45°=BC/AB
1=20/AB
AB=20 m
In right △ABD,
tan60°=BD/AB
√3=h+20/20
h=20(√3-1)m
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