Question

from a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20m high building are 45 deg and 60 deg, respectively. find the height of the tower.​

Answer 1

Answer:

➱14.64m

Step-by-step explanation:

➱let height of transmission tower = 'h' m

& AB = 'x' m

➵In triangle ABC,

$\tan(θ) = \frac{bc}{ab} \\ \tan(45) = \frac{20}{x} \\ 1 = \frac{20}{x} \\ x = 20m$

➵Again in triangle ABD,

$\tan(θ) = \frac{bd}{ab} \\ \tan(60) = \frac{20 + h}{x} \\ \sqrt{3} = \frac{20 + h}{20} \\ h = 20 \sqrt{3} - 20 \\ h = 20( \sqrt{3} - 1) \\ h = 20(1.732 - 1) \\ h = 20 \times 0.732 \\ h = 14.640$

➵Hence, height of tower = 14.64 m

➱Original answer☑

Answer 2

Answer:

elevation=deviation=answer