Question

From a point on the level ground, the angle of elevation of the top of a tower is 30°. On proceeding 30 m towards the tower the angle of elevation becomes 60°. Find the height of the tower.

Answer 1

Answer:

From △ACD,AD=x3

From △ACD,100+xAD=Tan300=31

⇒AD=3100+x

Equating two equation, we get

x=50⇒h=503 metres

Answer 2

Step-by-step explanation:

let the triangle be ABCD then angle B=90degree,angeBCA=60;

angle ACD 120;angle D=30 degree;

angle BAC=30 .

So, BC=x m;

AC=20 m bcoz angle ACD=angle ADC=30 degree;

therefore AC=CD=20m.

Let  AB-h m

then;

sin 60=h/20

therefore h=10root 3 meters.