Question

from a point P on a level ground the angle of elevation on top of the tower is 30°. if the tower is 100m high, how far is P from the foot of the tower

Answer 1

Let AB be the tower.
Then, APB = 30º and AB = 100 m.
AB/AP=tan 30º=1/√3
⇒ AP = (AB × √3)m
          = 100√3m
          = (100 × 1.73)m
          = 173m

Answer 2

----------------------------------------

Here is the solution:

----------------------------------------

Given that the angle of elevation is 30º and the tower is 100 m high.

Define x:

Let x be the distance from P to the foot of the tower.

Find the distance from P to the foot of the tower:

tan  θ = opp/adj

tan 30 = 100/x

1/√3 = 100/x

x = 100√3 m  

Answer: The distance is  100√3 m