Question

from a point p outside the circle with centre o two tangents PA and PB are drawn to meet the circle at A and B respectively if APB =70° then ∆ OAB isequal to​

Answer 1

Answer:

APB=70 degree

AOB = 110 degree(cyclic Quadri..)

triangle AOB iso celes

so, angle OAB = (180-110)/2 = 35

degree

angleOAB = 35 degree