Question

From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to the diameter of the circle, show that triangle APB is equilateral.

Answer 1

Since OBP=90 and OB is rad while OP=2rad Sin OPB=0.5,angle OPB=30. By sym APB=60. PAB=PBA=(180-60)/2=60. Thus trngl PAB is eqltrl.