Question

From a point P, which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pair of tangents PQ and PR are drawn to the circle. Then the area of the quadrilateral PQOR ((in cm2 ) is:​

Answer 1

Answer:

The radius perpendicular tangent at the pt. of contact, therefore, OQ⊥PQ and OR⊥PR

In rt. △OPQ, we have

PQ=OP2−OQ2

   =169−25=144=12 cm

⇒ PR=12 cm (Two tangents from the same external pt. to a circle are equal)

Now area of quad. PQOR=2×Area of △POQ

   =(2×21×12×5) cm2=60 cm2

Step-by-step explanation:

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