From a point P which is at a distance of 13 cm from the centre O of a circle of radius 5 cm, the pair of tangents PQ and PR to the circle are drawn.
Answers
Hey mate here is your answer
Answer:
60cm
Step-by-step explanation:
Clearly tangent PQ and PR are perpendicular to OQ and OR respectively.
Hence, both triangle POQ and PQR are right angled
PQ = √OP² - OQ² = √13² - 5² = 12cm
Area of triangle POQ = OQ x PQ / 2 = 5 x 12 / 2 =30 cm²
Similarly,
Area of triangle POR = OR x PR / 2 = 5 x 12 / 2 = 30 cm²
Area of quadrilateral PQOR = 30 + 30 = 60cm
Hope it helped you
Answer:
60 cm
Step-by-step explanation:
tangent PQ and PR are perpendicular to OQ and OR respectively.
Hence, both triangle POQ and PQR are right angled
PQ = √OP² - OQ² = √13² - 5² = 12cm
Area of triangle POQ = OQ x PQ / 2 = 5 x 12 / 2 =30 cm²
Similarly,
Area of triangle POR = OR x PR / 2 = 5 x 12 / 2 = 30 cm²
Area of quadrilateral PQOR = 30 + 30 = 60cm