Question

from a point Q; the length of the tangent to a circle is 24 CM and the distance of Q from the centre is 25 CM. find the radius of the circle

Answer 1

Let the radius be 'r' and the centre be 'O'.
Therefore, by pythagoras theorem,
r=
$\sqrt{25 {}^{2} - 24 ^{2} }$
r=
$\sqrt{625 - 576}$
r=
$\sqrt{49}$
r=7
Therefore, radius=7 cm

Answer 2

Let the radius be 'r' and the centre be 'O'.
Therefore, by pythagoras theorem,
r=
\sqrt{25 {}^{2} - 24 ^{2} }252−242​ 
r=
\sqrt{625 - 576}625−576​ 
r=
\sqrt{49}49​ 
r=7
Therefore, radius=7 cm