From a point q the length of the tangent to a circle is 40cm and the distance of q from the centre is 41cm. find radius
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Answered by
15
given,length=40cm
d=41 cm
to find radius=l*d/2= 40*41/2
=820 cm
d=41 cm
to find radius=l*d/2= 40*41/2
=820 cm
Answered by
29
Let Bq be the tangent from point q of length 40 cm
Aq = 41
Since,
The tangent at any point of circle is perpendicular to the radius through the point of contact.
|_ABq = 90°
Hence , ∆ABq is a right angle triangle.
Using Pythagoras theorem in ∆ABq
Aq² = AB² + BQ²
( 41 )² = AB² + ( 40 )²
1681 = AB² + 1600
1681 - 1600 = AB²
81 = AB²
√81 = AB
±9 = AB
Since radius can't be negative
so radius = 9cm
Aq = 41
Since,
The tangent at any point of circle is perpendicular to the radius through the point of contact.
|_ABq = 90°
Hence , ∆ABq is a right angle triangle.
Using Pythagoras theorem in ∆ABq
Aq² = AB² + BQ²
( 41 )² = AB² + ( 40 )²
1681 = AB² + 1600
1681 - 1600 = AB²
81 = AB²
√81 = AB
±9 = AB
Since radius can't be negative
so radius = 9cm
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