from a point T which is at a distance of 13 cm from the centre of a circle of radius 5cm the pair of tangents TA and TB to the circle drawn. the perimeter of quadrilateral taob is equal to
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tangents are of same length
=13^2-5^2
=144
=12
perimeter=2(12+5)
=17×2
=34 cm
=13^2-5^2
=144
=12
perimeter=2(12+5)
=17×2
=34 cm
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