Question

From
a
quadeatic equation whose gootie
5 + 3 and 5-
$5 + \sqrt{3} and 5 - \sqrt{3}$
13​

Answer 1

Step-by-step explanation:

Let ,

$\alpha = 5 + \sqrt{3} \\ \beta = 5 - \sqrt{3}$

$\alpha + \beta = 5 + \sqrt{3} + 5 - \sqrt{3}$

$\alpha + \beta = 10$

$\alpha \beta = (5 + \sqrt{3} )(5 - \sqrt{3} )$

$\alpha \beta = 25 - 3 = 22$

Therefore , the quadratic equation is ,

${x}^{2} - ( \alpha + \beta )x + \alpha \beta$

${x}^{2} - 10x + 22$

Therefore, it is your answer. I hope it helps you.