Question

From a quadratic polynamial whose zeros are 3+root2 and3-root2

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

${x}^{2} - 6x + 7 = 0$

Step-by-step explanation:

we need formula

x square-(sum of roots )x+( product of roots) = 0

now

xsquare-(3+√2+3-√2)x+9-20=0

xsquare-6x+7=0