Question

from a quadratic polynomial PX with -1 / 6 and -1/3 as the sum and product of its zeros respectively​

Answer 1

Step-by-step explanation:

Let a and b be the roots of the quadratic polynomial.

A/q,

a+b = - 1/6

a*b = - 1/3

Quadratic polynomial =

x2 - (a+b) x + ab

= x2 + x/6 - 1/3

=6x2 + x - 2

Answer 2

Hey MATE!

To form a quadratic equation with roots α,β we use thr formula :

x^2 -{sum of roots}*x - {product of roots}

=> x^2 -{α+β}x - {αβ}

Since we are directly provided with the values of (α+β) and (αβ) so we put them in the formula.

=> x^2 - (-1/6)x - (-1/3)

=> x^2 - (-1/6)x - (-1/3)

=> x^2 + x/6 + 1/3

It Is the required Q. E

Hope it helps

HAKUNA MATATA :))