from a quadratic polynomial PX with -1 / 6 and -1/3 as the sum and product of its zeros respectively
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Answered by
3
Step-by-step explanation:
Let a and b be the roots of the quadratic polynomial.
A/q,
a+b = - 1/6
a*b = - 1/3
Quadratic polynomial =
x2 - (a+b) x + ab
= x2 + x/6 - 1/3
=6x2 + x - 2
Answered by
2
Hey MATE!
To form a quadratic equation with roots α,β we use thr formula :
x^2 -{sum of roots}*x - {product of roots}
=> x^2 -{α+β}x - {αβ}
Since we are directly provided with the values of (α+β) and (αβ) so we put them in the formula.
=> x^2 - (-1/6)x - (-1/3)
=> x^2 - (-1/6)x - (-1/3)
=> x^2 + x/6 + 1/3
It Is the required Q. E
Hope it helps
HAKUNA MATATA :))
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