Question

from a quadratic polynomial whose one of the zeros is 9-root7​

Answer 1

Answer:

$\alpha =9-\sqrt{7}$

thus the other zero will be $9+\sqrt{7}$

$\beta =9+\sqrt{7}$

$\alpha +\beta =(9-\sqrt{7})+(9+\sqrt{7})=9+9=18$

$\alpha \beta =(9-\sqrt{7})(9+\sqrt{7})=(9)^{2}-(\sqrt{7})^{2}=81-7=74$

we know that the polynomial is always of the form :

$p(x) = x^{2}-(\alpha +\beta )x+\alpha \beta \\\\p(x)=x^{2}-(18)x+74\\\\p(x)=x^{2}-18x+74$

I hope this helps.....

Answer 2

Answer:

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