From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameter is cut off. Find the area of remining paper (use π = 22/7)
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Answer:
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Explanation:
Area of rectangular sheet of paper = Area of rectangle = length × breadth = 40 × 28 = 1120 cm2
Area of semicircular cut out = 1/2 πr2
Area of remaining sheet of paper = Area of rectangular sheet of paper – Area of semicircular cut out.
Therefore, area of remaining sheet of paper is 812 cm2.
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Step I :-
Finding the area of rectangular sheet.
Where,
- Length = 40 cm
- Breadth = 28 cm
There area:-
Substitute the values,
∴ Area of rectangular sheet of paper is 1120cm².
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Step ll:-
We know, BC is the diameter of the semi-circle.
Where,
- Diameter (d) = 28cm
- Therefore, Radius (r) = 28 ÷ 2 = 14cm
- Taking π = 22/7 (given)
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- Finding the Area of semi-circular cut off from the sheet.
Formula using here,
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On substituting the Values,
Cancel 196 by 7, we get
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Area of remaining sheet = Area of rectangular sheet – Area of semi-circular cut off.
= 1120 – 308
= 812
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The area of remaining sheet of paper is 812cm².
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